A mortar launches a 8.50-kg fireworks shell straight up with an initial speed of 62.6 m/s.How high does the shell go?

Question

Quizplus · Accepted Answer

We can use the fact that the maximum height reached by the shell is given by the formula:

h = (v^2 / 2g)

where h is the height, v is the initial velocity, and g is the acceleration due to gravity.

We know that the initial velocity is 62.6 m/s, and the acceleration due to gravity is approximately 9.81 m/s^2. Plugging in these values, we get:

h = (62.6^2) / (2 * 9.81) ≈ 200 m

Therefore, the shell reaches a maximum height of approximately 200 meters. The answer is choice C.

A Mortar Launches a 8