A force has the dependence F_x = -ax⁴ on the position x.The work performed by this force when the position of its point of application changes from 0.75 m to 1.50 m is -32.2 J.the constant a is

Question

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The work done by the force is the integral of F(x) from 0.75 to 1.50. Solving the integral and setting it equal to -32.2 J gives a = 21.9 N/m^4.

A Force Has the Dependence Fx = -Ax4 on the Position

A Force Has the Dependence F_x = -Ax⁴ on the Position