A 0.5-kg ball is thrown vertically upward with an initial velocity of 10 m/s.What is the change in the ball's kinetic energy between the starting point and the highest point in the trajectory?

Question

Quizplus · Accepted Answer

At the highest point in its trajectory, the ball's velocity is 0 m/s, meaning all its initial kinetic energy has been converted into potential energy. The change in kinetic energy (ΔKE) can be calculated using the formula ΔKE = 0.5 * m * (v_final^2 - v_initial^2). Plugging in the values (m = 0.5 kg, v_initial = 10 m/s, v_final = 0 m/s), we get ΔKE = 0.5 * 0.5 * (0^2 - 10^2) = -25 J. This indicates a decrease in kinetic energy, hence the correct answer is -25 J.

A 05-Kg Ball Is Thrown Vertically Upward with an Initial Velocity