An 85.0-kg snowboarder slides down a frictionless slope inclined at an angle of 30 $\circ$ .What is her acceleration? A)1.18 m/s² B)2.49 m/s² C)4.91 m/s² D)9.81 m/s²

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Quizplus · Accepted Answer

The acceleration of the snowboarder can be found using the formula $a = g \sin(\theta)$, where $g = 9.81 \, m/s^2$ is the acceleration due to gravity and $\theta = 30^\circ$. Substituting the given values, $a = 9.81 \sin(30^\circ) = 9.81 \times 0.5 = 4.905 \, m/s^2$, which rounds to $4.91 \, m/s^2$.

An 850-Kg Snowboarder Slides Down a Frictionless Slope Inclined at an an Angle