A football resting on the ground is kicked at an angle of 35.0 $\circ$ towards the uprights with an initial speed of 20.0 m/s.What is the maximum height (in meters)reached by the ball?
A)1.75
B)6.71
C)3.12
D)0.12
E)9.24

Question

Quizplus · Accepted Answer

To find the maximum height reached by the football, we use the formula for the vertical component of the projectile motion: $h = \frac{v^2 \sin^2(\theta)}{2g}$, where $v$ is the initial speed, $\theta$ is the launch angle, and $g$ is the acceleration due to gravity (approximately $9.8 \, \text{m/s}^2$). Plugging in the given values: $h = \frac{(20.0 \, \text{m/s})^2 \sin^2(35^\circ)}{2 \times 9.8 \, \text{m/s}^2}$, we find that the maximum height $h \approx 6.71 \, \text{m}$.

A Football Resting on the Ground Is Kicked at an Angle