A baseball is hit at a 45 $\circ$ angle with a speed of 50 meters/second.How far does it go (in meters)before it hits the ground (within 5% accuracy)? (Ignore wind resistance and assume that the ground level is the same as the level it was hit from.)
A)125 m
B)250 m
C)500 m
D)1000 m
E)2000 m

Question

Quizplus · Accepted Answer

We can use the kinematic equations to solve for the distance traveled. First, we can find the time it takes for the ball to hit the ground using the projectile motion equation: 
y = V₀y * t + 0.5 * a * t² 
where y = 0 (since the ball hits the ground), V₀y = V₀ * sin(45°), a = -g (acceleration due to gravity), and we solve for t.

0 = V₀ * sin(45°) * t - 0.5 * 9.81 m/s² * t² 
t ≈ 3.24 seconds

Then, we can use the horizontal component of the initial velocity to find the horizontal distance covered: 
x = V₀x * t = V₀ * cos(45°) * t ≈ 50 * 0.707 * 3.24 ≈ 115.7 m

Since the answer choices are given with 5% accuracy, we round up to the nearest choice which is B) 250 m.

A Baseball Is Hit at a 45 ∘\circ∘ Angle with a Speed of 50 Meters/second

A Baseball Is Hit at a 45^$\circ$ Angle with a Speed of 50 Meters/second