A vector with magnitude 25.0 m points along the positive x direction.If it is rotated by 50.0 degrees counterclockwise,what are the components of the vector? A)A_x = 25.0 sin 50.0 $\circ$ and A_y = 25.0 cos 50.0 $\circ$ B)A_x = 25.0 cos 50.0 $\circ$ and A_y = 25.0 sin 50.0 $\circ$ C)A_x = 25.0 sin 310 $\circ$ and A_y = 25.0 cos 310 $\circ$ D)A_x = 25.0 cos 310 $\circ$ and A_y = 25.0 sin 310 $\circ$

Question

Quizplus · Accepted Answer

To find the components of the vector after rotating counterclockwise by 50 degrees, we need to use the following formulas: A_x = magnitude of the original vector * cos(angle of rotation) A_y = magnitude of the original vector * sin(angle of rotation) Since the original vector points along the positive x direction, its angle with the positive x axis is 0 degrees. Adding 50 degrees counterclockwise gives us an angle of 50 degrees with the positive x axis. Plugging in the values, we get: A_x = 25.0 * cos(50) = 16.03 A_y = 25.0 * sin(50) = 19.12 Therefore, choice B is the correct answer.

A Vector with Magnitude 25 ∘\circ∘ and Ay = 25

A Vector with Magnitude 25 $\circ$ and A_y = 25