In the water molecule,the hydrogen and oxygen atoms are separated by 10^-10 m and the bond angle between the two hydrogen-oxygen bonds is 105 $\circ$ .the mass of the hydrogen atom is 1 u and that of the oxygen atom is 16 u.The center of mass of the water molecule along the line of symmetry from the oxygen atom is A)6.76 * 10^-12 m B)8.91 * 10^-12 m C)10.1 * 10^-12 m D)14.6 * 10^-12 m E)17.8 * 10^-12 m

Question

Quizplus · Accepted Answer

The center of mass (COM) of a system can be found using the formula: $COM = \frac{\sum m_i x_i}{\sum m_i}$, where $m_i$ and $x_i$ are the mass and position of the ith particle, respectively. For a water molecule, considering the oxygen atom at the origin and the line of symmetry as the x-axis, the hydrogen atoms are equidistant from the oxygen atom. The mass of the hydrogen atom is 1 u, and the mass of the oxygen atom is 16 u. The distance between the hydrogen and oxygen atoms is $10^{-10}$ m. The COM, considering the symmetry and the masses, will be closer to the oxygen atom due to its significantly higher mass. Calculating the exact position requires considering the molecule's geometry, but the correct answer is based on the principle that the COM will be located along the line of symmetry closer to the oxygen atom due to its greater mass.

In the Water Molecule,the Hydrogen and Oxygen Atoms Are Separated ∘\circ∘

In the Water Molecule,the Hydrogen and Oxygen Atoms Are Separated $\circ$