A car accelerates from $5.0 \mathrm {~m} / \mathrm { s }$ to $21 \mathrm {~m} / \mathrm { s }$ at a constant rate of $3.0 \mathrm {~m} / \mathrm { s } ^ { 2 }$ How far does it travel while accelerating?
A) 69 m
B) 207 m
C) 41 m
D) 117 m

Question

Quizplus · Accepted Answer

The car's initial velocity is 5.0 m/s, its final velocity is 21 m/s, and its acceleration is 3.0 m/s^2. We can use the following equation to calculate the distance traveled while accelerating:```distance = (final velocity^2 - initial velocity^2) / (2 * acceleration)```Plugging in the values we know, we get:```distance = (21 m/s)^2 - (5.0 m/s)^2) / (2 * 3.0 m/s^2) = 69 m```Therefore, the car travels 69 m while accelerating.

A Car Accelerates From 5.0 m/s5.0 \mathrm {~m} / \mathrm { s }5.0 m/s

A Car Accelerates From $5.0 \mathrm {~m} / \mathrm { s }$