A cat leaps to try to catch a bird. If the cat's jump was at 60° off the ground and its initial velocity was $2.74 \mathrm {~m} / \mathrm { s }$ what is the highest point of its trajectory, neglecting air resistance?
A) 0.29 m
B) 0.58 m
C) 10.96 m
D) 0.19 m

Question

Quizplus · Accepted Answer

The vertical component of the velocity is $v_{y} = 2.74 \sin(60^\circ)$. Using the formula for maximum height $h = \frac{v_{y}^2}{2g}$, where $g = 9.81 \, \mathrm{m/s^2}$, the height is approximately 0.29 m.

A Cat Leaps to Try to Catch a Bird 2.74 m/s2.74 \mathrm {~m} / \mathrm { s }2.74 m/s

A Cat Leaps to Try to Catch a Bird $2.74 \mathrm {~m} / \mathrm { s }$