A 450-kg sports car accelerates from rest to 100 km/h in 4.80 s.What magnitude force does a 68.0 kg passenger experience during the acceleration?
A)394 N
B)82.0 N
C)342 N
D)311 N

Question

Quizplus · Accepted Answer

The force experienced by the passenger can be calculated using Newton's second law, $F = ma$, where $m$ is the mass of the passenger and $a$ is the acceleration of the car. First, convert the car's acceleration from km/h to m/s: $100 \, \text{km/h} = \frac{100 \times 1000}{3600} \, \text{m/s} = 27.78 \, \text{m/s}$. The acceleration $a$ is then found by dividing the change in velocity by the time, $a = \frac{27.78 \, \text{m/s}}{4.80 \, \text{s}} = 5.79 \, \text{m/s}^2$. Applying Newton's second law for the passenger, $F = 68.0 \, \text{kg} \times 5.79 \, \text{m/s}^2 = 393.72 \, \text{N}$, which rounds to $394 \, \text{N}$.

A 450-Kg Sports Car Accelerates from Rest to 100 Km/h