At their closest approach,Venus and Earth are 4.20 × 10¹⁰ m apart.The mass of Venus is 4.87 × 10²⁴ kg,the mass of Earth is 5.97 × 10²⁴ kg,and G = 6.67 × 10^-11 N ∙ m²/kg².What is the magnitude of the gravitational force exerted by Venus on Earth at that point? A)1.10 × 10¹⁸ N B)4.62 × 10²⁸ N C)5.43 × 10²⁶ N D)6.30 × 10²⁰ N E)1.72 × 10¹⁹ N

Question

Quizplus · Accepted Answer

The gravitational force can be calculated using Newton's law of universal gravitation: $F = \frac{G \cdot m_1 \cdot m_2}{r^2}$, where $G = 6.67 \times 10^{-11} \, \text{N} \cdot \text{m}^2/\text{kg}^2$, $m_1 = 4.87 \times 10^{24} \, \text{kg}$ (mass of Venus), $m_2 = 5.97 \times 10^{24} \, \text{kg}$ (mass of Earth), and $r = 4.20 \times 10^{10} \, \text{m}$ (distance between Venus and Earth). Plugging these values into the formula gives a force of approximately $1.10 \times 10^{18} \, \text{N}$.

At Their Closest Approach,Venus and Earth Are 4