Find the orbital speed of an ice cube in the rings of Saturn.The mass of Saturn is 5.68 x 10²⁶ kg,and use an orbital radius of 1.00 x 10⁵ km.(G = 6.67 × 10^-11 N ∙ m²/kg²) A)19.5 km/s B)27.5 km/s C)13.8 km/s

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The correct answer is A because the orbital speed of an ice cube in the rings of Saturn is 19.5 km/s. This is because the orbital speed of an object is given by the equation v = sqrt(GM/r), where G is the gravitational constant, M is the mass of the object being orbited, and r is the orbital radius. In this case, the mass of Saturn is 5.68 x 10^26 kg, the orbital radius is 1.00 x 10^5 km, and the gravitational constant is 6.67 x 10^-11 N ∙ m^2/kg^2. Plugging these values into the equation, we get v = sqrt((6.67 x 10^-11 N ∙ m^2/kg^2) * (5.68 x 10^26 kg) / (1.00 x 10^5 km)) = 19.5 km/s.

Find the Orbital Speed of an Ice Cube in the Rings