A 60.0-kg man stands at one end of a 20.0-kg uniform 10.0-m long board.How far from the man is the center of mass (or center of gravity)of the man-board system?
A)1.25 m
B)2.50 m
C)5.00 m
D)7.50 m
E)9.00 m

Question

Quizplus · Accepted Answer

The center of mass of the system can be calculated using the formula: (m1*x1 + m2*x2) / (m1 + m2). Here, m1 = 60 kg, x1 = 0 m (man's position), m2 = 20 kg, x2 = 5 m (center of the board). The center of mass is (60*0 + 20*5) / (60 + 20) = 1.25 m from the man.

A 600-Kg Man Stands at One End of a 20