An electrical motor spins at a constant $2695.0 \mathrm { rpm } .$ If the rotor radius is $7.165 \mathrm {~cm}$ what is the linear acceleration of the edge of the rotor? A) 5707 m/s² B) 281.6 m/s² C) 572,400 m/s² D) 28.20 m/s²

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Quizplus · Accepted Answer

The linear acceleration of the edge of the rotor is given by:$$a = r \omega^2$$where:* $r$ is the radius of the rotor* $\omega$ is the angular velocity of the rotorIn this problem, we have:* $r = 7.165 \mathrm {~cm} = 0.07165 \mathrm {~m}$* $\omega = 2695.0 \mathrm {~rpm} = 283.2 \mathrm {~rad/s}$Substituting these values into the equation, we get:$$a = (0.07165 \mathrm {~m})(283.2 \mathrm {~rad/s})^2 = 5707 \mathrm {~m/s^2}$$Therefore, the linear acceleration of the edge of the rotor is 5707 m/s².

An Electrical Motor Spins at a Constant 2695.0rpm.2695.0 \mathrm { rpm } .2695.0rpm.

An Electrical Motor Spins at a Constant $2695.0 \mathrm { rpm } .$