A 600-kg car makes a 90° turn. Its speed before the turn is 21.0 m/s and after the turn it is 24.0 m/s. What is the magnitude of the change in the car's momentum during the turn? A) 19.1 × 10³ kg∙m/s B) 10.2 × 10³ kg∙m/s C) 9.55 × 10³ kg∙m/s D) 12.0 × 10³ kg∙m/s E) 22.2 × 10³ kg∙m/s

Question

Quizplus · Accepted Answer

The change in momentum is equal to the final momentum minus the initial momentum. The final momentum is 600 kg * 24.0 m/s = 14400 kg∙m/s. The initial momentum is 600 kg * 21.0 m/s = 12600 kg∙m/s. Therefore, the change in momentum is 14400 kg∙m/s - 12600 kg∙m/s = 1800 kg∙m/s.

A 600-Kg Car Makes a 90° Turn