What is the minimum energy needed to change the speed of a 1600-kg sport utility vehicle from 15.0 m/s to 40.0 m/s?
A)1.10 MJ
B)10.0 kJ
C)20.0 kJ
D)40.0 kJ
E)0.960 MJ

Question

Quizplus · Accepted Answer

The minimum energy needed can be calculated using the kinetic energy formula: $ \Delta KE = \frac{1}{2} m (v_f^2 - v_i^2) $, where $ m = 1600 \, \text{kg} $, $ v_f = 40.0 \, \text{m/s} $, and $ v_i = 15.0 \, \text{m/s} $. Plugging in the values, $ \Delta KE = \frac{1}{2} \times 1600 \times (40^2 - 15^2) = 1.10 \times 10^6 \, \text{J} = 1.10 \, \text{MJ} $.

What Is the Minimum Energy Needed to Change the Speed