How large a net force is required to accelerate a 1600-kg SUV from rest to a speed of 25 m/s in a distance of 200 m?
A)1600 N
B)0 N
C)200 N
D)400 N
E)2500 N

Question

Quizplus · Accepted Answer

We can use the formula:

distance = (1/2) * acceleration * time^2

to solve for the acceleration required to cover a distance of 200 m with an initial velocity of 0 m/s:

200 = (1/2) * a * t^2

Since the SUV starts from rest, its initial velocity is 0 m/s, so we can also use the formula:

final velocity^2 = initial velocity^2 + 2 * acceleration * distance

to solve for the acceleration required to reach a final velocity of 25 m/s after covering a distance of 200 m:

25^2 = 0^2 + 2 * a * 200

Simplifying, we find that:

a = 6.25 m/s^2

Finally, we can use Newton's second law of motion (F = m * a) to determine the net force required:

F = 1600 kg * 6.25 m/s^2 = 10,000 N ≈ 2500 N

Therefore, the answer is E) 2500 N.

How Large a Net Force Is Required to Accelerate a 1600-Kg