A 50-g ball moving at 10 m/s in the +x direction suddenly collides head-on with a stationary ball of mass 100 g.If the collision is perfectly elastic,what is the velocity of each ball immediately after the collision?
A)-3.3 m/s,+6.7 m/s
B)+3.3 m/s,-6.7 m/s
C)-6.7 m/s,+3.3 m/s
D)+6.7 m/s,-3.3 m/s

Question

Quizplus · Accepted Answer

In a perfectly elastic collision, both momentum and kinetic energy are conserved. For the 50-g ball (m1) moving at 10 m/s (v1) colliding with a stationary 100-g ball (m2), the final velocities (v1' and v2') can be found using the conservation equations. The final velocity of the first ball (v1') is given by v1' = [(m1 - m2) / (m1 + m2)] * v1, which calculates to -3.3 m/s, indicating it moves in the opposite direction post-collision. The final velocity of the second ball (v2') is given by v2' = [(2*m1) / (m1 + m2)] * v1, which calculates to +6.7 m/s, indicating it moves forward post-collision.

A 50-G Ball Moving at 10 M/s in the +X