A refrigerator has an interior volume of 0.500 m³.The temperature inside the refrigerator in 282 K,and the pressure is 101 kPa.If the molecular weight of air is 29 g/mol,what is the mass of air inside the refrigerator? (R = 8.31 J/mol × K) A)625 g B)513 g C)447 g D)329 g E)243 g

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Quizplus · Accepted Answer

The mass of air inside the refrigerator can be calculated using the ideal gas law:PV = nRTwhere P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.We can rearrange this equation to solve for n:n = PV/RTWe can then use the molar mass of air to convert the number of moles to mass:mass = n * molar massPlugging in the given values, we get:n = (101 kPa * 0.500 m^3) / (8.31 J/mol * K * 282 K) = 21.5 molmass = 21.5 mol * 29 g/mol = 623.5 gTherefore, the mass of air inside the refrigerator is 623.5 g, which is closest to choice A) 625 g.

A Refrigerator Has an Interior Volume of 0