The density of material at the center of a neutron star is approximately 1.00 × 10¹⁸ kg/m³. What is the mass of a cube of this material that is $1.76 \text { microns }$ on each side. (One micron is equal to 1.00 × 10^-6 m.) A) 5.45 kg B) 4.74 kg C) 6.16 kg D) 6.70 kg

Question

Quizplus · Accepted Answer

The volume of the cube is $(1.76 \times 10^{-6} \text{ m})^3 = 5.45 \times 10^{-18} \text{ m}^3$. The mass is density times volume: $1.00 \times 10^{18} \text{ kg/m}^3 \times 5.45 \times 10^{-18} \text{ m}^3 = 5.45 \text{ kg}$.

The Density of Material at the Center of a Neutron 1.76 microns 1.76 \text { microns }1.76 microns

The Density of Material at the Center of a Neutron $1.76 \text { microns }$