A 12,000-N car is raised using a hydraulic lift,which consists of a U-tube with arms of unequal areas,filled with oil and capped at both ends with tight-fitting pistons.The wider arm of the U-tube has a radius of 18.0 cm and the narrower arm has a radius of 5.00 cm.The car rests on the piston on the wider arm of the U-tube.The pistons are initially at the same level.What is the initial force that must be applied to the smaller piston in order to start lifting the car? For purposes of this problem,neglect the weight of the pistons.

Question

Quizplus · Accepted Answer

The force applied on the smaller piston is determined using Pascal's principle, which states that pressure is transmitted undiminished in an enclosed fluid. The pressure needed to lift the car is the same on both pistons. The force on the larger piston is F1 = 12,000 N. The area of the larger piston is A1 = π(0.18 m)^2, and the area of the smaller piston is A2 = π(0.05 m)^2. Using the formula F1/A1 = F2/A2, we solve for F2: F2 = F1 * (A2/A1) = 12,000 N * (π(0.05 m)^2 / π(0.18 m)^2) = 926 N.

A 12,000-N Car Is Raised Using a Hydraulic Lift,which Consists