What buoyant force does a 0.60-kg solid gold crown experience when it is immersed in water? The density of gold is 19.3 × 10³ kg/m³ and that of water is 1000 kg/m³. A)3.0 × 10^-5 N B)3.0 × 10^-4 N C)3.0 × 10^-2 N D)0.30 N

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Quizplus · Accepted Answer

The buoyant force on an object immersed in a fluid is equal to the weight of the fluid displaced by the object. The volume of the crown can be found using its mass and the density of gold: Volume = mass / density = 0.60 kg / (19.3 × 10^3 kg/m^3) = 3.11 × 10^-5 m^3. The weight of the water displaced is equal to the volume displaced times the density of water times gravity (9.8 m/s^2): Buoyant force = 3.11 × 10^-5 m^3 × 1000 kg/m^3 × 9.8 m/s^2 = 0.30 N.

What Buoyant Force Does a 0