An object undergoing simple harmonic motion has a maximum displacement of $6.2 \mathrm {~m}$ at $t = 0.00 \mathrm {~s}$ If the angular frequency of oscillation is $1.6 \mathrm { rad } / \mathrm { s } \text {, }$ what is the object's displacement when $t = 3.5 \mathrm {~s} ?$
A) 4.8 m
B) 5.6 m
C) 3.7 m
D) 3.1 m

Question

Quizplus · Accepted Answer

The correct answer is A.The object's displacement is given by the equation:$$x = A \cos(\omega t)$$where A is the maximum displacement, $\omega$ is the angular frequency, and t is the time.At t = 0.00 s, the object's displacement is 6.2 m, so A = 6.2 m.At t = 3.5 s, the object's displacement is:$$x = 6.2 \cos(1.6 	imes 3.5) = 4.8 \mathrm {~m}$$

An Object Undergoing Simple Harmonic Motion Has a Maximum Displacement 6.2 m6.2 \mathrm {~m}6.2 m

An Object Undergoing Simple Harmonic Motion Has a Maximum Displacement $6.2 \mathrm {~m}$