A ball is attached to an ideal spring and oscillates with a period T. If the mass of the ball is doubled, what is the new period?
A) 2T
B) T/2
C) T
D) T $\sqrt { 2 }$
E) T/ $\sqrt { 2 }$

Question

Quizplus · Accepted Answer

The period of a spring-mass system is given by T = 2π $\sqrt { \frac { m }{ k } }$, where m is the mass of the ball and k is the spring constant. If the mass is doubled, the period becomes T' = 2π $\sqrt { \frac { 2m }{ k } }$. Notice that T' = T $\sqrt { 2 }$. Therefore, the new period is D) T $\sqrt { 2 }$.

A Ball Is Attached to an Ideal Spring and Oscillates 2\sqrt { 2 }2​

A Ball Is Attached to an Ideal Spring and Oscillates $\sqrt { 2 }$