A stretched string is observed to have four equal segments in a standing wave driven at a frequency of 480 Hz.What driving frequency will set up a standing wave with five equal segments?
A)600 Hz
B)360 Hz
C)240 Hz
D)120 Hz

Question

Quizplus · Accepted Answer

The frequency is directly proportional to the number of segments (or antinodes) in a standing wave. If 4 segments correspond to 480 Hz, then 5 segments, which is 1.25 times more segments, will correspond to a frequency that is 1.25 times higher, thus 480 Hz * 1.25 = 600 Hz.

A Stretched String Is Observed to Have Four Equal Segments