An organ pipe open at both ends has a length of 0.80 m. If the velocity of sound in air is $340 \mathrm {~m} / \mathrm { s } \text {, }$ what is the frequency of the second harmonic of this pipe?
A) 213 Hz
B) 425 Hz
C) 638 Hz
D) 850 Hz

Question

Quizplus · Accepted Answer

The frequency of the second harmonic for an open pipe is given by $ f_2 = \frac{2v}{L} $. Substituting $ v = 340 \, \text{m/s} $ and $ L = 0.80 \, \text{m} $, we get $ f_2 = \frac{2 \times 340}{0.80} = 850 \, \text{Hz} $.

An Organ Pipe Open at Both Ends Has a Length 340 m/s, 340 \mathrm {~m} / \mathrm { s } \text {, }340 m/s,

An Organ Pipe Open at Both Ends Has a Length $340 \mathrm {~m} / \mathrm { s } \text {, }$