In a two-slit experiment, the slit separation is 3.00 × 10^{- 5} m. The interference pattern is created on a screen that is 2.00 m away from the slits. If the 7th bright fringe on the screen is 10.0 cm away from the central fringe, what is the wavelength of the light? A) 100 nm B) 204 nm C) 214 nm D) 224 nm E) 234 nm

Question

Quizplus · Accepted Answer

The distance between the central fringe and the nth bright fringe is given by:
y = nλL/d
where y is the distance on the screen, λ is the wavelength of light, L is the distance from the slits to the screen, and d is the slit separation.

Substituting the given values:
n = 7, y = 0.1 m, L = 2 m, d = 3.00 × 10-5 m

0.1 = (7)λ(2) / (3.00 × 10-5)
λ = 214 nm

Therefore, the answer is C.

In a Two-Slit Experiment, the Slit Separation Is 3