Coherent light of wavelength 540 nm passes through a pair of thin slits that are 3.4 × $10 ^ { - 5 }$ m apart. At what angle away from the centerline does the second bright fringe occur?

Question

Quizplus · Accepted Answer

The second bright fringe occurs at an angle given by:$$	heta = \sin^{-1} \left(\frac{m \lambda}{d}ight)$$where m is the order of the fringe (m = 2 for the second bright fringe), λ is the wavelength of the light, and d is the distance between the slits. Plugging in the given values, we get:$$	heta = \sin^{-1} \left(\frac{2 	imes 540 	imes 10^{-9} 	ext{ m}}{3.4 	imes 10^{-5} 	ext{ m}}ight) = 1.8^\circ$$

Coherent Light of Wavelength 540 Nm Passes Through a Pair 10−510 ^ { - 5 }10−5

Coherent Light of Wavelength 540 Nm Passes Through a Pair $10 ^ { - 5 }$