A student constructs an astronomical telescope with a magnification of 10.If the telescope has an objective lens of focal length 0.50 m,what is the resulting length of the telescope?
A)53 cm
B)55 cm
C)60 cm
D)75 cm

Question

Quizplus · Accepted Answer

The length of the telescope is the sum of the focal lengths of the objective lens and the eyepiece. Given magnification (m) = 10 and focal length of the objective lens (f_o) = 0.50 m, we use the formula for magnification of a telescope in normal adjustment, m = f_o / f_e, where f_e is the focal length of the eyepiece. Solving for f_e gives f_e = f_o / m = 0.50 m / 10 = 0.05 m = 5 cm. Therefore, the total length of the telescope is f_o + f_e = 0.50 m + 0.05 m = 0.55 m = 55 cm.

A Student Constructs an Astronomical Telescope with a Magnification of 10.If