Two +6.0-µC charges are placed at two of the vertices of an equilateral triangle having sides 2.0 m long. What is the electric potential at the third vertex, relative to infinity, due to these charges? (k = 1/4πε₀ = 9.0 × 10⁹ N ∙ m²/C²)

Question

Quizplus · Accepted Answer

The electric potential at a point due to a point charge is given by V = kQ/r. For two charges, the potentials add up. Here, V = 2 * (9.0 × 10^9 N∙m²/C² * 6.0 × 10^-6 C / 2.0 m) = 54,000 V = 54 kV.

Two +60-µC Charges Are Placed at Two of the Vertices of of an Equilateral