A proton moves 0.10 m along the direction of an electric field of magnitude 3.0 V/m. What is the change in kinetic energy of the proton? (e = 1.60 × 10^-19 C)

Question

Quizplus · Accepted Answer

The change in kinetic energy of a charged particle moving in an electric field is given by ΔK = qEd, where q is the charge of the particle, E is the electric field strength, and d is the distance moved in the field. Substituting the given values, we get ΔK = (1.60 × 10^-19 C)(3.0 V/m)(0.10 m) = 4.8 × 10^-20 J. Therefore, the best choice is A.

A Proton Moves 0