A light bulb operating at a dc voltage of 120 V has a resistance of 200 Ω.How much power is dissipated in this bulb?
A)100 W
B)60 W
C)72 W
D)14 mW
E)7.2 W

Name: A light bulb operating at a dc voltage of 120 V has a resistance of 200 Ω.How much power is dissipated in this bulb? A)100 W B)60 W C)72 W D)14 mW E)7.2 W
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Question

Quizplus · Accepted Answer

We can use the formula P = V^2 / R to calculate the power dissipated by the bulb.

P = (120 V)^2 / 200 Ω
P = 14,400 / 200
P = 72 W

Therefore, the power dissipated by the bulb is 72 W.

A Light Bulb Operating at a Dc Voltage of 120