A 2.0-m straight wire carrying a current of 0.60 A is oriented parallel to a uniform magnetic field of 0.50 T.What is the magnitude of the magnetic force on it?
A)zero
B)0.15 N
C)0.30 N
D)0.60 N

Question

Quizplus · Accepted Answer

The magnetic force on a current-carrying wire is given by $F = ILB \sin(\theta)$, where $I$ is the current, $L$ is the length of the wire, $B$ is the magnetic field strength, and $\theta$ is the angle between the wire and the magnetic field. Since the wire is parallel to the magnetic field, $\theta = 0^\circ$, making $\sin(\theta) = 0$. Therefore, $F = 0$, indicating no magnetic force acts on the wire.

A 20-M Straight Wire Carrying a Current of 0