A straight wire is carrying a current of 2.0 A.It is placed at an angle of 60° with respect to a magnetic field of strength 0.20 T.If the wire experiences a force of 0.40 N,what is the length of the wire?
A)1.0 m
B)1.2 m
C)1.4 m
D)1.6 m
E)1.8 m

Question

Quizplus · Accepted Answer

The force experienced by a current-carrying wire in a magnetic field is given by the equation $F = BIL\sin(\theta)$, where $F$ is the force, $B$ is the magnetic field strength, $I$ is the current, $L$ is the length of the wire, and $\theta$ is the angle between the wire and the magnetic field. Rearranging the equation to solve for $L$, we get $L = \frac{F}{B I \sin(\theta)}$. Substituting the given values, $L = \frac{0.40}{0.20 \times 2.0 \times \sin(60^\circ)}$, and since $\sin(60^\circ) = \sqrt{3}/2$, we find $L = 1.2$ meters.

A Straight Wire Is Carrying a Current of 2