A straight 1.0-m long wire is carrying a current.The wire is placed perpendicular to a magnetic field of strength 0.20 T.If the wire experiences a force of 0.60 N,what is the current in the wire?

Question

Quizplus · Accepted Answer

The force on a current-carrying wire in a magnetic field is given by F = BIL, where F is the force, B is the magnetic field strength, I is the current, and L is the length of the wire. Rearranging for I gives I = F / (BL). Substituting the given values: I = 0.60 N / (0.20 T * 1.0 m) = 3.0 A.

A Straight 1