Two long parallel wires that are 0.30 m apart carry currents of 5.0 A and 8.0 A in the opposite direction.Find the magnitude of the force per unit length that each wire exerts on the other wire and indicate if the force is attractive or repulsive.(μ₀ = 4π × 10^-7 T ∙ m/A) A)2.7 × 10^-5 N repulsive B)7.2 × 10^-5 N repulsive C)3.4 × 10^-5 N attractive D)2.7 × 10^-5 N attractive E)7.2 × 10^-5 N attractive

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Quizplus · Accepted Answer

The force between two parallel wires carrying currents in opposite directions is repulsive. The magnitude of the force per unit length is given by:$$F = \frac{\mu_0 I_1 I_2}{2\pi d}$$where:* μ0 is the permeability of free space (4π × 10^-7 T ∙ m/A)* I1 and I2 are the currents in the wires (5.0 A and 8.0 A)* d is the distance between the wires (0.30 m)Plugging in the values, we get:$$F = \frac{(4\pi 	imes 10^{-7} 	ext{ T} \cdot 	ext{m/A})(5.0 	ext{ A})(8.0 	ext{ A})}{2\pi (0.30 	ext{ m})}$$$$F = 2.7 	imes 10^{-5} 	ext{ N/m}$$Therefore, the magnitude of the force per unit length that each wire exerts on the other wire is 2.7 × 10^-5 N, and the force is repulsive.

Two Long Parallel Wires That Are 0