A flat circular loop carrying a current of 2.0 A is in a magnetic field of 3.5 T.The loop has an area of 0.12 m² and its plane is oriented at a 37° angle to the field.What is the magnitude of the magnetic torque on the loop? A)0.10 N ∙ m B)0.51 N ∙ m C)0.67 N ∙ m D)46 N ∙ m

Question

Quizplus · Accepted Answer

The formula for magnetic torque is τ = NABsinθ, where N is the number of turns, A is the area of the loop, B is the magnetic field strength, and θ is the angle between the plane of the loop and the direction of the magnetic field.
In this case, N = 1 (there is only one loop), A = 0.12 m^2, B = 3.5 T, and θ = 37°. Plugging in these values, we get:
τ = (1)(0.12 m^2)(3.5 T)sin37°
τ = 0.67 N ∙ m
Therefore, the correct answer is (C) 0.67 N ∙ m.

A Flat Circular Loop Carrying a Current of 2