A long wire carrying a 2.0-A current is placed along the y-axis.What is the magnitude of the magnetic field at a point that is 0.60 m from the origin along the x-axis? (μ₀ = 4π × 10^-7 T ∙ m/A) A)0.67 µT B)1.3 µT C)0.12 µT D)6.7 T E)12 T

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The magnitude of the magnetic field created by a long straight current-carrying wire at a distance $r$ from the wire is given by the formula $B = \frac{\mu_0 I}{2\pi r}$, where $\mu_0 = 4\pi \times 10^{-7} \, \text{T} \cdot \text{m/A}$, $I$ is the current, and $r$ is the distance from the wire. Plugging in the given values ($I = 2.0 \, \text{A}$ and $r = 0.60 \, \text{m}$), we get $B = \frac{4\pi \times 10^{-7} \times 2.0}{2\pi \times 0.60} = \frac{4 \times 10^{-7} \times 2.0}{1.2} = \frac{8 \times 10^{-7}}{1.2} = 6.67 \times 10^{-7} \, \text{T} = 0.67 \, \mu\text{T}$.

A Long Wire Carrying a 2