A round flat conducting loop is placed perpendicular to a uniform 0.50 T magnetic field. If the area of the loop increases at a rate of 3.0 × $10^{ - 3}$ $m ^ { 2 }$ /s, what is the induced emf in the loop?
A) 4.3 mV
B) 0 mV
C) 1.5 mV
D) 1.7 mV
E) 5.5 mV

Question

Quizplus · Accepted Answer

The induced emf (ε) is given by Faraday's law of electromagnetic induction: ε = -dΦ/dt, where Φ is the magnetic flux. Since Φ = B * A and B is constant, dΦ/dt = B * dA/dt. Given B = 0.50 T and dA/dt = 3.0 × 10^-3 m²/s, ε = 0.50 * 3.0 × 10^-3 = 1.5 mV.

A Round Flat Conducting Loop Is Placed Perpendicular to a Uniform