An astronaut on a spaceship moving at 0.927c says that the trip between two stationary stars took $4.26 \mathrm { y }$ How long does this journey appear to take to someone in the rest frame of the two stars?
A) 11.4 y
B) 1.60 y
C) 2.30 y
D) 12.6 y

Question

Quizplus · Accepted Answer

The time dilation formula is $ t = \frac{t_0}{\sqrt{1 - v^2/c^2}} $. Here, $ t_0 = 4.26 $ y, $ v = 0.927c $. Plugging in these values, we find $ t \approx 11.4 $ y.

An Astronaut on a Spaceship Moving at 0 4.26y4.26 \mathrm { y }4.26y

An Astronaut on a Spaceship Moving at 0 $4.26 \mathrm { y }$