Someone in Earth's rest frame says that a spaceship's trip between two planets took 10.0 y, while an astronaut on the space ship says that the trip took $5.78 \mathrm { y }$ What is the speed of the spaceship, assuming the planets are at essentially at rest?
A) 0.816 c
B) 0.735 c
C) 0.975 c
D) 0.384 c

Question

Quizplus · Accepted Answer

The time dilation formula $ t = \frac{t_0}{\sqrt{1 - v^2/c^2}} $ can be used, where $ t = 10.0 $ y, $ t_0 = 5.78 $ y. Solving for $ v $, we find $ v \approx 0.816c $.

Someone in Earth's Rest Frame Says That a Spaceship's Trip 5.78y5.78 \mathrm { y }5.78y

Someone in Earth's Rest Frame Says That a Spaceship's Trip $5.78 \mathrm { y }$