What is the wavelength of a 6.32-eV photon? (c = 3.00 × 10⁸ m/s,h = 6.626 × 10^-34 J ∙ s,1 eV = 1.60 × 10^-19J) A)197 nm B)167 nm C)216 nm D)234 nm

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Quizplus · Accepted Answer

The wavelength of a photon can be calculated using the formula λ = hc/E, where h is Planck's constant, c is the speed of light, and E is the energy of the photon. First, convert the energy from eV to Joules: 6.32 eV * 1.60 × 10^-19 J/eV = 1.0112 × 10^-18 J. Then, λ = (6.626 × 10^-34 J∙s * 3.00 × 10^8 m/s) / 1.0112 × 10^-18 J ≈ 197 nm.

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