The wavelength of a ruby laser is 694.3 nm.What is the energy difference between the two energy states for the transition that produces this light? (c = 3.00 × 10⁸ m/s,1 eV = 1.60 × 10^-19J,h = 6.626 × 10^-34 J ∙ s)

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Quizplus · Accepted Answer

The energy difference ($E$) between the two energy states can be calculated using the equation $E = \frac{hc}{\lambda}$, where $h$ is Planck's constant, $c$ is the speed of light, and $\lambda$ is the wavelength of the light. Substituting the given values: $E = \frac{(6.626 \times 10^{-34} \text{ J s})(3.00 \times 10^8 \text{ m/s})}{694.3 \times 10^{-9} \text{ m}}$. Converting the result to electron volts (eV) using $1 \text{ eV} = 1.60 \times 10^{-19} \text{ J}$, the calculation yields approximately 1.79 eV.

The Wavelength of a Ruby Laser Is 694