A hydrogen atom is excited to the n = 9 level.Its decay to the n = 6 level detected in a photographic plate.What is the frequency of the light photographed? (1 eV = 1.60 × 10^-19J,h = 6.626 × 10^-34 J ∙ s) A)5.08 × 10¹³ Hz B)5,910 Hz C)5,910 nm D)3.28 × 10^-9 km

Question

Quizplus · Accepted Answer

We can use the formula for calculating the frequency of light emitted during a transition in a hydrogen atom:

v = R*(1/n1^2 - 1/n2^2)

where R is the Rydberg constant, n1 and n2 are the initial and final energy levels, respectively.

Substituting n1 = 9 and n2 = 6, and using the value of R, we get:

v = 3.29 × 10^15 Hz

This matches with option A, which is the correct answer.

A Hydrogen Atom Is Excited to the N = 9