A hydrogen atom is in its n = 2 excited state when its electron absorbs $9.5 \mathrm { eV }$ in an interaction with a photon. What is the energy of the resulting free electron?
A) 6.1 eV
B) 7.9 eV
C) 8.2 eV
D) 9.2 eV

Question

Quizplus · Accepted Answer

The energy required to ionize a hydrogen atom from the n = 2 state is 3.4 eV. When the electron absorbs 9.5 eV, it uses 3.4 eV to escape, leaving 6.1 eV as the kinetic energy of the free electron.

A Hydrogen Atom Is in Its N = 2 Excited 9.5eV9.5 \mathrm { eV }9.5eV

A Hydrogen Atom Is in Its N = 2 Excited $9.5 \mathrm { eV }$