The equation shows a fission reaction: $^{235}_{92}$ U + $^{1}_{0}$n → $^{99}_{41}$Nb + X + 4 $^{1}_{0}$ n What is the missing term X in the equation?

Question

Quizplus · Accepted Answer

The sum of atomic numbers and mass numbers must be equal on both sides of the equation. The atomic number on the left is 92 (U) + 0 (n) = 92. On the right, it is 41 (Nb) + X + 0 (4n). For mass numbers, it is 235 (U) + 1 (n) = 236 on the left, and 99 (Nb) + X + 4 (n) = 236 on the right. Solving these gives X as $^{133}_{51}$ Sb.

The Equation Shows a Fission Reaction 92235^{235}_{92}92235​ U 01^{1}_{0}01​ N → 4199^{99}_{41}4199​

The Equation Shows a Fission Reaction $^{235}_{92}$ U $^{1}_{0}$ N → $^{99}_{41}$