In the nuclear reaction $^{ 16 } _{ 8 }O + ^{4}
_{2}
He → X + ^{19}
_{10}
Ne$ , what is X?

Name: In the nuclear reaction $^{ 16 } _{ 8 }O + ^{4} _{2} He → X + ^{19} _{10} Ne$ , what is X?
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Question

In the nuclear reaction $^{ 16 } _{ 8 }O + ^{4}
_{2}
 He → X + ^{19}
_{10}
 Ne$ , what is X?

Quizplus · Accepted Answer

The total mass and atomic numbers must be conserved. The mass number on the left is 20 (16+4), and on the right, it is 22 (19+3). The atomic number on the left is 10 (8+2), and on the right, it is 10. Therefore, X must be a neutron to balance the mass number.

In the Nuclear Reaction 816O+24He→X+1019Ne^{ 16 } _{ 8 }O + ^{4}_{2} He → X + ^{19}_{10} Ne816​O+24​He→X+1019​Ne

In the Nuclear Reaction $^{ 16 } _{ 8 }O + ^{4}_{2} He → X + ^{19}_{10} Ne$