Consider the nuclear reaction: ⁷Li + ¹p → ⁴He + ⁴He. The known atomic masses are ⁷Li: 7.016005 u $^{4} _{2} He$ : 4.002603 u ¹p: 1.007825 u
What is the Q-value (or reaction energy) of this reaction?
(1 u = 931.5 MeV/c²)

Question

Consider the nuclear reaction: ⁷Li + ¹p → ⁴He + ⁴He. The known atomic masses are ⁷Li: 7.016005 u

^{4} _{2} He

: 4.002603 u ¹p: 1.007825 u
What is the Q-value (or reaction energy) of this reaction?
(1 u = 931.5 MeV/c²)

Quizplus · Accepted Answer

The Q-value is calculated by finding the mass difference between the reactants and products and converting it to energy. The mass of reactants is 7.016005 u + 1.007825 u = 8.02383 u. The mass of products is 2 * 4.002603 u = 8.005206 u. The mass difference is 8.02383 u - 8.005206 u = 0.018624 u. Converting this to energy: 0.018624 u * 931.5 MeV/u = 17.35 MeV.

Consider the Nuclear Reaction: 7Li + 1p → 4He 24He^{4} _{2} He24​He

Consider the Nuclear Reaction: ⁷Li + ¹p → ⁴He $^{4} _{2} He$