Figure 6S-1
Customers Enter a Haberdashery That Sells Only Ascots

Figure 6S-1
Customers enter a haberdashery that sells only ascots, cufflinks and suspenders and are served by the owner operator. The owner is the only employee, so if customer B arrives while customer A is being served, customer B must patiently wait until customer A exits the system. Customers are always willing to wait regardless of how long their wait is. The interarrival and service times are uniformly distributed and shown in the table below.
$$\begin{array} { | c | c | c | } \hline \text { Range } & \text { Interarrival (min) } & \text { Service (min) } \\\hline 0.000 - 0.200 & 3 & 6 \\\hline 0.201 - 0.400 & 6 & 7 \\\hline 0.401 - 0.600 & 9 & 8 \\\hline 0.601 - 0.800 & 12 & 9 \\\hline 0.801 - 1.000 & 15 & 10 \\\hline\end{array}$$ The stream of random number for a Monte Carlo simulation of the system appear in this table>
$$\begin{array} { | c | c | } \hline \text { Interarrival } & \text { Service } \\\hline .114 & .979 \\\hline .899 & .297 \\\hline .925 & .162 \\\hline .085 & .574 \\\hline .824 & .235 \\\hline .151 & .593 \\\hline .223 & .956 \\\hline .477 & .845 \\\hline\end{array}$$
-Use the data from Figure 6S-1. What is the total time that customers must wait from 8:00 am to 9:15 am?

A) 17 minutes
B) 18 minutes
C) 19 minutes
D) 20 minutes